64/x^2+1=2x/x-4

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Solution for 64/x^2+1=2x/x-4 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

64/(x^2)+1 = (2*x)/x-4 // - (2*x)/x-4

64/(x^2)-((2*x)/x)+1+4 = 0

64/(x^2)-2+1+4 = 0

64*x^-2 = -3 // : 64

x^-2 = -3/64

-2 < 0

1/(x^2) = -3/64 // * x^2

1 = -3/64*x^2 // : -3/64

-64/3 = x^2

x belongs to the empty set

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